Optimal. Leaf size=139 \[ \frac{12 i f^2 (e+f x) \text{PolyLog}\left (3,-i e^{c+d x}\right )}{a d^3}-\frac{6 i f (e+f x)^2 \text{PolyLog}\left (2,-i e^{c+d x}\right )}{a d^2}-\frac{12 i f^3 \text{PolyLog}\left (4,-i e^{c+d x}\right )}{a d^4}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}+\frac{i (e+f x)^4}{4 a f} \]
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Rubi [A] time = 0.212735, antiderivative size = 139, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.207, Rules used = {5559, 2190, 2531, 6609, 2282, 6589} \[ \frac{12 i f^2 (e+f x) \text{PolyLog}\left (3,-i e^{c+d x}\right )}{a d^3}-\frac{6 i f (e+f x)^2 \text{PolyLog}\left (2,-i e^{c+d x}\right )}{a d^2}-\frac{12 i f^3 \text{PolyLog}\left (4,-i e^{c+d x}\right )}{a d^4}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}+\frac{i (e+f x)^4}{4 a f} \]
Antiderivative was successfully verified.
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Rule 5559
Rule 2190
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{(e+f x)^3 \cosh (c+d x)}{a+i a \sinh (c+d x)} \, dx &=\frac{i (e+f x)^4}{4 a f}+2 \int \frac{e^{c+d x} (e+f x)^3}{a+i a e^{c+d x}} \, dx\\ &=\frac{i (e+f x)^4}{4 a f}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}+\frac{(6 i f) \int (e+f x)^2 \log \left (1+i e^{c+d x}\right ) \, dx}{a d}\\ &=\frac{i (e+f x)^4}{4 a f}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}-\frac{6 i f (e+f x)^2 \text{Li}_2\left (-i e^{c+d x}\right )}{a d^2}+\frac{\left (12 i f^2\right ) \int (e+f x) \text{Li}_2\left (-i e^{c+d x}\right ) \, dx}{a d^2}\\ &=\frac{i (e+f x)^4}{4 a f}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}-\frac{6 i f (e+f x)^2 \text{Li}_2\left (-i e^{c+d x}\right )}{a d^2}+\frac{12 i f^2 (e+f x) \text{Li}_3\left (-i e^{c+d x}\right )}{a d^3}-\frac{\left (12 i f^3\right ) \int \text{Li}_3\left (-i e^{c+d x}\right ) \, dx}{a d^3}\\ &=\frac{i (e+f x)^4}{4 a f}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}-\frac{6 i f (e+f x)^2 \text{Li}_2\left (-i e^{c+d x}\right )}{a d^2}+\frac{12 i f^2 (e+f x) \text{Li}_3\left (-i e^{c+d x}\right )}{a d^3}-\frac{\left (12 i f^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(-i x)}{x} \, dx,x,e^{c+d x}\right )}{a d^4}\\ &=\frac{i (e+f x)^4}{4 a f}-\frac{2 i (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{a d}-\frac{6 i f (e+f x)^2 \text{Li}_2\left (-i e^{c+d x}\right )}{a d^2}+\frac{12 i f^2 (e+f x) \text{Li}_3\left (-i e^{c+d x}\right )}{a d^3}-\frac{12 i f^3 \text{Li}_4\left (-i e^{c+d x}\right )}{a d^4}\\ \end{align*}
Mathematica [A] time = 0.0779278, size = 118, normalized size = 0.85 \[ \frac{i \left (-\frac{24 f \left (d^2 (e+f x)^2 \text{PolyLog}\left (2,-i e^{c+d x}\right )-2 d f (e+f x) \text{PolyLog}\left (3,-i e^{c+d x}\right )+2 f^2 \text{PolyLog}\left (4,-i e^{c+d x}\right )\right )}{d^4}-\frac{8 (e+f x)^3 \log \left (1+i e^{c+d x}\right )}{d}+\frac{(e+f x)^4}{f}\right )}{4 a} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.118, size = 635, normalized size = 4.6 \begin{align*}{\frac{ie{f}^{2}{x}^{3}}{a}}+{\frac{6\,i{e}^{2}fcx}{da}}-{\frac{6\,ie{f}^{2}{c}^{2}x}{a{d}^{2}}}-{\frac{6\,i{e}^{2}fc\ln \left ({{\rm e}^{dx+c}} \right ) }{a{d}^{2}}}+{\frac{6\,ie{f}^{2}{c}^{2}\ln \left ({{\rm e}^{dx+c}} \right ) }{a{d}^{3}}}+{\frac{6\,i{e}^{2}fc\ln \left ({{\rm e}^{dx+c}}-i \right ) }{a{d}^{2}}}-{\frac{6\,ie{f}^{2}{c}^{2}\ln \left ({{\rm e}^{dx+c}}-i \right ) }{a{d}^{3}}}-{\frac{6\,i{e}^{2}f\ln \left ( 1+i{{\rm e}^{dx+c}} \right ) x}{da}}-{\frac{6\,i{e}^{2}f\ln \left ( 1+i{{\rm e}^{dx+c}} \right ) c}{a{d}^{2}}}-{\frac{6\,ie{f}^{2}\ln \left ( 1+i{{\rm e}^{dx+c}} \right ){x}^{2}}{da}}+{\frac{6\,ie{f}^{2}\ln \left ( 1+i{{\rm e}^{dx+c}} \right ){c}^{2}}{a{d}^{3}}}-{\frac{12\,ie{f}^{2}{\it polylog} \left ( 2,-i{{\rm e}^{dx+c}} \right ) x}{a{d}^{2}}}-{\frac{12\,i{f}^{3}{\it polylog} \left ( 4,-i{{\rm e}^{dx+c}} \right ) }{a{d}^{4}}}+{\frac{{\frac{i}{4}}{x}^{4}{f}^{3}}{a}}+{\frac{{\frac{3\,i}{2}}{e}^{2}f{x}^{2}}{a}}-{\frac{i{e}^{3}x}{a}}+{\frac{2\,i{f}^{3}{c}^{3}x}{a{d}^{3}}}+{\frac{2\,i{f}^{3}{c}^{3}\ln \left ({{\rm e}^{dx+c}}-i \right ) }{a{d}^{4}}}-{\frac{4\,ie{f}^{2}{c}^{3}}{a{d}^{3}}}+{\frac{3\,i{e}^{2}f{c}^{2}}{a{d}^{2}}}-{\frac{6\,i{e}^{2}f{\it polylog} \left ( 2,-i{{\rm e}^{dx+c}} \right ) }{a{d}^{2}}}+{\frac{12\,ie{f}^{2}{\it polylog} \left ( 3,-i{{\rm e}^{dx+c}} \right ) }{a{d}^{3}}}-{\frac{2\,i{f}^{3}{c}^{3}\ln \left ({{\rm e}^{dx+c}} \right ) }{a{d}^{4}}}-{\frac{2\,i{f}^{3}{c}^{3}\ln \left ( 1+i{{\rm e}^{dx+c}} \right ) }{a{d}^{4}}}-{\frac{2\,i{f}^{3}\ln \left ( 1+i{{\rm e}^{dx+c}} \right ){x}^{3}}{da}}-{\frac{6\,i{f}^{3}{\it polylog} \left ( 2,-i{{\rm e}^{dx+c}} \right ){x}^{2}}{a{d}^{2}}}+{\frac{12\,i{f}^{3}{\it polylog} \left ( 3,-i{{\rm e}^{dx+c}} \right ) x}{a{d}^{3}}}-{\frac{2\,i\ln \left ({{\rm e}^{dx+c}}-i \right ){e}^{3}}{da}}+{\frac{{\frac{3\,i}{2}}{f}^{3}{c}^{4}}{a{d}^{4}}}+{\frac{2\,i\ln \left ({{\rm e}^{dx+c}} \right ){e}^{3}}{da}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.64123, size = 356, normalized size = 2.56 \begin{align*} -\frac{i \, e^{3} \log \left (i \, a \sinh \left (d x + c\right ) + a\right )}{a d} - \frac{6 i \,{\left (d x \log \left (i \, e^{\left (d x + c\right )} + 1\right ) +{\rm Li}_2\left (-i \, e^{\left (d x + c\right )}\right )\right )} e^{2} f}{a d^{2}} - \frac{i \,{\left (f^{3} x^{4} + 4 \, e f^{2} x^{3} + 6 \, e^{2} f x^{2}\right )}}{4 \, a} - \frac{6 i \,{\left (d^{2} x^{2} \log \left (i \, e^{\left (d x + c\right )} + 1\right ) + 2 \, d x{\rm Li}_2\left (-i \, e^{\left (d x + c\right )}\right ) - 2 \,{\rm Li}_{3}(-i \, e^{\left (d x + c\right )})\right )} e f^{2}}{a d^{3}} - \frac{2 i \,{\left (d^{3} x^{3} \log \left (i \, e^{\left (d x + c\right )} + 1\right ) + 3 \, d^{2} x^{2}{\rm Li}_2\left (-i \, e^{\left (d x + c\right )}\right ) - 6 \, d x{\rm Li}_{3}(-i \, e^{\left (d x + c\right )}) + 6 \,{\rm Li}_{4}(-i \, e^{\left (d x + c\right )})\right )} f^{3}}{a d^{4}} + \frac{i \, d^{4} f^{3} x^{4} + 4 i \, d^{4} e f^{2} x^{3} + 6 i \, d^{4} e^{2} f x^{2}}{2 \, a d^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 2.17348, size = 752, normalized size = 5.41 \begin{align*} \frac{i \, d^{4} f^{3} x^{4} + 4 i \, d^{4} e f^{2} x^{3} + 6 i \, d^{4} e^{2} f x^{2} + 4 i \, d^{4} e^{3} x + 8 i \, c d^{3} e^{3} - 12 i \, c^{2} d^{2} e^{2} f + 8 i \, c^{3} d e f^{2} - 2 i \, c^{4} f^{3} - 48 i \, f^{3}{\rm polylog}\left (4, -i \, e^{\left (d x + c\right )}\right ) +{\left (-24 i \, d^{2} f^{3} x^{2} - 48 i \, d^{2} e f^{2} x - 24 i \, d^{2} e^{2} f\right )}{\rm Li}_2\left (-i \, e^{\left (d x + c\right )}\right ) +{\left (-8 i \, d^{3} e^{3} + 24 i \, c d^{2} e^{2} f - 24 i \, c^{2} d e f^{2} + 8 i \, c^{3} f^{3}\right )} \log \left (e^{\left (d x + c\right )} - i\right ) +{\left (-8 i \, d^{3} f^{3} x^{3} - 24 i \, d^{3} e f^{2} x^{2} - 24 i \, d^{3} e^{2} f x - 24 i \, c d^{2} e^{2} f + 24 i \, c^{2} d e f^{2} - 8 i \, c^{3} f^{3}\right )} \log \left (i \, e^{\left (d x + c\right )} + 1\right ) +{\left (48 i \, d f^{3} x + 48 i \, d e f^{2}\right )}{\rm polylog}\left (3, -i \, e^{\left (d x + c\right )}\right )}{4 \, a d^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f x + e\right )}^{3} \cosh \left (d x + c\right )}{i \, a \sinh \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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